# Show that the perpendicular let fall from any point on the straight line 2x + 11y – 5 = 0 upon the two straight lines 24x + 7y = 20 and 4x – 3y – 2 = 0 are equal to each other.

Given:

Lines 24x + 7y = 20 and 4x – 3y – 2 = 0

To prove:

The perpendicular let fall from any point on the straight line 2x + 11y – 5 = 0 upon the two straight lines 24x + 7y = 20 and 4x – 3y – 2 = 0 are equal to each other.

Concept Used:

Distance of a point from a line.

Assuming:

P(a, b) be any point on 2x + 11y 5 = 0

Explanation:

2a + 11b 5 = 0

b ……..(i)

Let d1 and d2 be the perpendicular distances from point P
on the lines 24x + 7y = 20 and 4x
3y 2 = 0, respectively.

d1 d1 From (1)

d1 Similarly,

d2 d2 From (1)

d2 d1 = d2

Hence proved.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Various Forms of Equations of line45 mins  Parametric Equations of Straight line48 mins  Slope, inclination and angle between two lines48 mins  Interactive Quiz on Equations of line23 mins  Straight line | Analyse your learning through quiz56 mins  General Equation of a line43 mins  Motion in a Straight Line - 0665 mins  Motion in a Straight Line - 0556 mins  Motion in a Straight Line - 0372 mins  Motion in a Straight Line - 1169 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 