Answer :
Given: p = 4, α = 15°
Concept Used:
Equation of line in normal form.
Explanation:
We know that, cos 15° = cos (45° – 30°) = cos45°cos30° + sin45°sin30°
cos(A – B) = cosAcosB + sinAsinB
And sin 15 = sin (45° – 30°) = sin 45° cos 30° – cos 45° sin 30°
sin (A – B) = sinAcosB – cosAsinB
So, the equation of the line in normal form is
Formula Used: x cos α + y sin α = p
⇒ (√3 + 1)x + (√3 – 1)y = 8√2
Hence, the equation of line in normal form is (√3 + 1)x + (√3–1)y = 8√2
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
<span lang="EN-US
RS Aggarwal - MathematicsThe distance betw
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal - MathematicsFind the equation
RD Sharma - MathematicsFind the equation
RD Sharma - MathematicsArea of the trian
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - MathematicsA point equidista
RD Sharma - Mathematics