Q. 165.0( 5 Votes )

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Answer :

Concept Used:

The equation of the line with intercepts a and b is


Given:


Here, a – b = 2


a = b + 2 ……(i)


Explanation:


The line is passing through (3,2).


……(ii)


From equation (i) and (ii)



3b + 2b +4 = b2 + 2b


b2 – 3b – 4 = 0


(b – 4)(b + 1) = 0b = 4, -1


Now, from equation (i)


For b = 4, a = 4 + 2 = 6


For b = -1, b = -1 + 2 = 1


Thus the equation of line is


or


x – y = 1 or 2x + 3y = 12


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