Q. 143.7( 3 Votes )

Find the equation

Answer :

Given, A line which passes through the point ( – 3,5) and perpendicular to the line joining (2,5) and ( – 3,6)

To Find: Find the equation


Formula Used: The equation of line is (y – y1) = m(x – x1)


Explanation: Here, The line passes through the point ( – 3,5 ), Given


So, The coordinate (x1,y1) = ( – 3,5)


Now, The line is perpendicular to the line joining (2,5) and ( – 3,6),


We know, The slope of the line with two points is, m =


So, the slope of line joining (2, 5 ) and ( – 3,6) is =


m =


Therefore, The slope of the required line is, m =


So, m =


m = 5


Now, The equation of straight line is (y – y1) = m(x – x1)


y – 5 = 5 (x – ( – 3)


y – 5 = 5x + 15


5x – y + 20 = 0


Hence, The equation of line is 5x – y + 20 = 0


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