Q. 145.0( 2 Votes )
Find the equation of the line passing through the point ( – 3, 5) and perpendicular to the line joining (2, 5) and ( – 3, 6).
Answer :
Given, A line which passes through the point ( – 3,5) and perpendicular to the line joining (2,5) and ( – 3,6)
To Find: Find the equation
Formula Used: The equation of line is (y – y1) = m(x – x1)
Explanation: Here, The line passes through the point ( – 3,5 ), Given
So, The coordinate (x1,y1) = ( – 3,5)
Now, The line is perpendicular to the line joining (2,5) and ( – 3,6),
We know, The slope of the line with two points is, m = 
So, the slope of line joining (2, 5 ) and ( – 3,6) is = 
m = 
Therefore, The slope of the required line is, m = 
So, m = 
m = 5
Now, The equation of straight line is (y – y1) = m(x – x1)
y – 5 = 5 (x – ( – 3)
y – 5 = 5x + 15
5x – y + 20 = 0
Hence, The equation of line is 5x – y + 20 = 0
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