# Find the equation of the line passing through the point ( – 3, 5) and perpendicular to the line joining (2, 5) and ( – 3, 6).

Given, A line which passes through the point ( – 3,5) and perpendicular to the line joining (2,5) and ( – 3,6)

To Find: Find the equation

Formula Used: The equation of line is (y – y1) = m(x – x1)

Explanation: Here, The line passes through the point ( – 3,5 ), Given

So, The coordinate (x1,y1) = ( – 3,5)

Now, The line is perpendicular to the line joining (2,5) and ( – 3,6),

We know, The slope of the line with two points is, m =

So, the slope of line joining (2, 5 ) and ( – 3,6) is =

m =

Therefore, The slope of the required line is, m =

So, m =

m = 5

Now, The equation of straight line is (y – y1) = m(x – x1)

y – 5 = 5 (x – ( – 3)

y – 5 = 5x + 15

5x – y + 20 = 0

Hence, The equation of line is 5x – y + 20 = 0

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