Q. 143.7( 8 Votes )

Find the equation

Answer :

To find:


The equation of the required line.


Assuming:


The line 3x + y = 12 intersect the x-axis and the y-axis at A and B, respectively.


y =m1x and m2x be the lines passing through the origin and trisect the line 3x + y =12 at P and Q.


Explanation:


At x = 0


0 + y =12


y =12


At y = 0


3x + 0 =12


x = 4


A (4, 0) and B (0,12)


y =m1x and m2x be the lines passing through the origin and trisect the line 3x + y =12 at P and Q.


AP = PQ = QB


Let us find the coordinates of P and Q.


P


Q


Clearly, P and Q lie on y = m1x and y = m2x, respectively.


4


m1 and m2 = 6


Hence, the required lines are y


2y = 3x and y = 6x


Hence, the equation of line is 2y = 3x and y = 6x


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