Answer :
To find:
The equation of the required line.
Assuming:
The line 3x + y = 12 intersect the x-axis and the y-axis at A and B, respectively.
y =m1x and m2x be the lines passing through the origin and trisect the line 3x + y =12 at P and Q.
Explanation:
At x = 0
0 + y =12
⇒ y =12
At y = 0
3x + 0 =12
⇒ x = 4
A (4, 0) and B (0,12)
y =m1x and m2x be the lines passing through the origin and trisect the line 3x + y =12 at P and Q.
AP = PQ = QB
Let us find the coordinates of P and Q.
P
Q
Clearly, P and Q lie on y = m1x and y = m2x, respectively.
4
⇒ m1 and m2 = 6
Hence, the required lines are y
⇒ 2y = 3x and y = 6x
Hence, the equation of line is 2y = 3x and y = 6x
Rate this question :
The equation of t
RD Sharma - MathematicsFind the equation
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - MathematicsFind the equation
RD Sharma - MathematicsFind the equation
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics