Answer :

Assuming:


AB be the given line which makes an angle of 1500 with the positive direction of y–axis and OQ be the perpendicular drawn from the origin on the line.


Given:


p = 7 and α = 30°


Explanation:


So, the equation of the line AB is


Formula Used: x cos α + y sin α = p


x cos 30° + y sin 30° = 7



√3 x + y = 14


Hence, the equation of line in normal form is √3 x + y = 14


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