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Given: (x1,y1) = A( – 1, – 3)

And tan θ = 1

To find:

The distance of a point from the line in the direction of the line.

Explanation:

So, the equation of the line passing through ( – 1, – 3) and having slope 1 is

Formula Used:

x – y = 2

Let x – y = 2 intersect the line 2x + y = 3 at point P.

Let AP = r

Then, the coordinate of P is given by

x and y

Thus, the coordinate of P is

Clearly, P lies on the line 2x + y = 3

3r

r

Hence, the distance of the point ( – 1, – 3) from the line 2x + y = 3 is

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