Q. 2 A

Find the equations to the sides of the triangles the coordinates of whose angular points are respectively:(1,4), (2, - 3) and (-1, - 2)

Given:

Points A (1, 4), B(2, -3) and C(-1, -2).

Assuming:

m1, m2, and m3 be the slope of the sides AB, BC and CA, respectively.

Concept Used:

The slope of the line passing through the two points ( x1, y1) and ( x2, y2).

The equation of the line passing through the two points ( x1, y1) and ( x2, y2).

To find:

The equation of sides of the triangle.

Explanation:

m1, m2m3

m1 = -7, m2 and m3 = 3

So, the equation of the sides AB, BC and CA are

Formula used: y – y1= m (x – x1)

y – 4 = -7 (x – 1), and y + 2 = 3(x+1)

7x + y =11, x+ 3y +7 =0 and 3x – y +1 = 0

Hence, equation of sides are 7x + y =11, x+ 3y +7 =0 and 3x – y +1 = 0

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