Answer :

Given, A line which is perpendicular and parallel to x–axis respectively and passing through (4, 3)

To Find: Find the equation of that line.


Formula used: The equation of line is [y – y1 = m(x – x1)]


Explanation:


Case 1 : When Line is parallel to x–axis


So, The parallel lines have equal slopes,


And, the slope of x–axis is always 0, then


The slope of line, m = 0


Coordinates of line are (x1, y1) = (4, 3)


The equation of line is y – y1 = m(x – x1) – – – – (1)


By putting the values in equation (1), we get


y – (3) = 0(x – 4)


y – 3 = 0


Case 2: when line is perpendicular to x–axis


Here, The line is perpendicular to the x–axis, then x is 0 and y is – 1.


So, The slope of the line is, m =


m =


Coordinates of line are (x1, y1) = (4, 3)


The equation of line = y – y1 = m(x – x1)


By putting the values, we get



x = 4


Hence, The equation of line when it is parallel to x –axis is y = 3 and it is perpendicular is x = 4.


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