Answer :

Given: equation is perpendicular to 3x – 4y + 11 = 0 and has y-intercept equal to


To find:


The equation of the straight line which has y-intercept equal to and is perpendicular to 3x – 4y + 11 = 0.


Explanation:


The line perpendicular to 3x 4y + 11 = 0 is 4x + 3y + λ = 0


It is given that the line 4x + 3y + λ = 0 has y – intercept equal to


This means that the line passes through


0 + 4 + λ = 0


λ = -4


Substituting the value of λ,


We get 4x + 3y – 4 = 0,


Hence, equation of the required line is 4x + 3y – 4 = 0


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