Answer :
Given: equation is perpendicular to 3x – 4y + 11 = 0 and has y-intercept equal to
To find:
The equation of the straight line which has y-intercept equal to and is perpendicular to 3x – 4y + 11 = 0.
Explanation:
The line perpendicular to 3x − 4y + 11 = 0 is 4x + 3y + λ = 0
It is given that the line 4x + 3y + λ = 0 has y – intercept equal to
This means that the line passes through
∴ 0 + 4 + λ = 0
⇒ λ = -4
Substituting the value of λ,
We get 4x + 3y – 4 = 0,
Hence, equation of the required line is 4x + 3y – 4 = 0
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