# Find the equation

Given: equation is perpendicular to x – 3y + 5 = 0 and passes through (3,-2)

To find:

Equation of required line.

Explanation:

The equation of the line perpendicular to x 3y + 5 = 0 is

3x + y + λ = 0,

Where λ is a constant.

It passes through (3, 2).

9 – 2 + λ = 0

λ = - 7

Substituting λ = 7 in 3x + y + λ = 0,

Hence, we get 3x + y – 7 = 0, which is the required line.

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