Find the equation

Given: equation is perpendicular to x – 3y + 5 = 0 and passes through (3,-2)

To find:

Equation of required line.

Explanation:

The equation of the line perpendicular to x − 3y + 5 = 0 is

3x + y + λ = 0,

Where λ is a constant.

It passes through (3, − 2).

9 – 2 + λ = 0

⇒ λ = - 7

Substituting λ = − 7 in 3x + y + λ = 0,

Hence, we get 3x + y – 7 = 0, which is the required line.