# Find the ratio in which the line 3x + 4y + 2 = 0 divides the distance between the lines 3x + 4y + 5 = 0 and 3x + 4y – 5 = 0

Given:

Lines A: 3x + 4y + 5 = 0 and B: 3x + 4y – 5 = 0

And also C: 3x + 4y + 2 = 0

To find:

Ratio in which line C divides the distance between the lines A and B

Explanation:

The distance between two parallel line ax + by + c1 = 0 and ax + by + c2 = 0 is

Therefore the distance between two parallel line 3x + 4y + 5 = 0 and 3x + 4y – 5 = 0 is

The distance between the line 3x + 4y + 2 = 0 and 3x + 4y – 5 = 0 is

Hence, the required ratio

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