Answer :

Given:


Lines A: 3x + 4y + 5 = 0 and B: 3x + 4y – 5 = 0


And also C: 3x + 4y + 2 = 0


To find:


Ratio in which line C divides the distance between the lines A and B


Explanation:


The distance between two parallel line ax + by + c1 = 0 and ax + by + c2 = 0 is



Therefore the distance between two parallel line 3x + 4y + 5 = 0 and 3x + 4y – 5 = 0 is



The distance between the line 3x + 4y + 2 = 0 and 3x + 4y – 5 = 0 is



Hence, the required ratio


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