Answer :

Concept Used:


The equation of a line in intercept form is


Given:


The line passes through (2, 1)


……(i)


Assuming:


The line 3x – 5y = 15 intercept the x-axis and the y-axis at A and B, respectively.


Explanation:


At x = 0 we have,


0– 5y = 15


5y = -15


y = -3


At y = 0 we have,


3x – 0 =15


x = 5


A= (0, -3) and B = (5, 0)


The midpoint of AB is ()


Clearly, the point () lies on the line


……(ii)


Using eq(i) + eq(ii) we get,



a


For a = we have,



b = 11


Therefore, the equation of the required line is:




5x + y = 11


Hence, the equation of line is 5x + y = 11


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