Q. 18

# <span lang="EN-US

Concept Used:

The equation of a line in intercept form is Given:

The line passes through (2, 1) ……(i)

Assuming:

The line 3x – 5y = 15 intercept the x-axis and the y-axis at A and B, respectively.

Explanation:

At x = 0 we have,

0– 5y = 15

5y = -15

y = -3

At y = 0 we have,

3x – 0 =15

x = 5

A= (0, -3) and B = (5, 0)

The midpoint of AB is ( )

Clearly, the point ( ) lies on the line  ……(ii)

Using eq(i) + eq(ii) we get, a For a = we have, b = 11

Therefore, the equation of the required line is:  5x + y = 11

Hence, the equation of line is 5x + y = 11

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

The equation of tRD Sharma - Mathematics

Find the equationRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

Find the equationRD Sharma - Mathematics

Find the equationRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics