Q. 15
Find the equation of the right bisector of the line segment joining the points A(1, 0) and B(2, 3).
Answer :
Given, The line segment joining the points (1,0) and (2,3)
To Find: Find the equation of line
Formula used: The equation of line is (y – y1) = m(x – x1)
Explanation: Here, The right bisector PQ of AB at C and is perpendicular to AB
So, The slope of the line with two points is, m 
The slope of the line AB 
We know, The product of two slopes of the perpendicular line is always – 1
Therefore, (slope of AB) × (slope of PQ) = – 1
Since Slope of PQ 
Now, The coordinate of the mid – points 
The coordinates of point C are 
The required equation of PQ is (y – y1) = m(x – x1)
6y – 9 = – 2x + 3
x + 3y = 6
Hence, The equation of line is x + 3y = 6
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