Q. 15

# Find the equation

Given, The line segment joining the points (1,0) and (2,3)

To Find: Find the equation of line

Formula used: The equation of line is (y – y1) = m(x – x1)

Explanation: Here, The right bisector PQ of AB at C and is perpendicular to AB

So, The slope of the line with two points is, m

The slope of the line AB

We know, The product of two slopes of the perpendicular line is always – 1

Therefore, (slope of AB) × (slope of PQ) = – 1

Since Slope of PQ

Now, The coordinate of the mid – points

The coordinates of point C are

The required equation of PQ is (y – y1) = m(x – x1)

6y – 9 = – 2x + 3

x + 3y = 6

Hence, The equation of line is x + 3y = 6

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