Q. 15

Find the equation of the right bisector of the line segment joining the points A(1, 0) and B(2, 3).

Answer :

Given, The line segment joining the points (1,0) and (2,3)

To Find: Find the equation of line


Formula used: The equation of line is (y – y1) = m(x – x1)


Explanation: Here, The right bisector PQ of AB at C and is perpendicular to AB


So, The slope of the line with two points is, m


The slope of the line AB


We know, The product of two slopes of the perpendicular line is always – 1


Therefore, (slope of AB) × (slope of PQ) = – 1


Since Slope of PQ


Now, The coordinate of the mid – points


The coordinates of point C are


The required equation of PQ is (y – y1) = m(x – x1)



6y – 9 = – 2x + 3


x + 3y = 6


Hence, The equation of line is x + 3y = 6


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