Answer :

Given:
2x
5y + 3 = 0 … (1)


5x 9y + λ = 0 … (2)


x 2y + 1 = 0 … (3)


To find:


Value of λ.


Concept Used:


Determinant of equation is zero.


Explanation:


It is given that the three lines are concurrent.



2(-9 + 2λ) + 5(5 – λ) + 3(-10 + 9) = 0


-18 + 4λ + 25 – 5λ – 3 = 0


λ = 4


Hence, λ = 4.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses