Q. 174.0( 4 Votes )

# The perpendicular

Given: perpendicular from the origin and meets at the point (-1, 2)

Explanation:

The given line is y = mx + c which can be written as mx –y + c = 0 … (1)

The slope of the line perpendicular to y = mx + c is So, the equation of the line with slope and passing through the origin is x + my = 0 … (2)

Solving eq(1) and eq(2) by cross multiplication, we get  Thus, the point of intersection of the perpendicular from the origin to the line y = mx + c is It is given that the perpendicular from the origin to the line y = mx + c meets it at the point (-1, 2) and m2 + 1 = mc and m2 + 1 mc m Now, substituting the value of m in m2 + 1 = mc, we get c Hence, m and c Rate this question :

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