Answer :
Given: perpendicular from the origin and meets at the point (-1, 2)
Explanation:
The given line is y = mx + c which can be written as mx –y + c = 0 … (1)
The slope of the line perpendicular to y = mx + c is
So, the equation of the line with slope and passing through the origin is
x + my = 0 … (2)
Solving eq(1) and eq(2) by cross multiplication, we get
Thus, the point of intersection of the perpendicular from the origin to the line y = mx + c is
It is given that the perpendicular from the origin to the line y = mx + c meets it at the point (-1, 2)
and
⇒ m2 + 1 = mc and m2 + 1
⇒ mc
⇒ m
Now, substituting the value of m in m2 + 1 = mc, we get
⇒ c
Hence, m and c
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