Answer :
We know that equation of line having angle θ from x–axis and passing through (x1, y1) is given by,
Therefore,
Equation of first line,
(y – 2)
y – 2 = √3x
y – √3x – 2 = 0
The equation of line parallel to this line and passing through (0, –2),
(y + 2) = √3x
y – √3x + 2 = 0
Equation of second line,
(y – 2)
y – 2 = –√3x
y + √3x – 2 = 0
The equation of line parallel to this line and passing through (0, –2),
(y + 2) = –√3x
y + √3x + 2 = 0
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