Answer :

We know that equation of line having angle θ from x–axis and passing through (x1, y1) is given by,



Therefore,


Equation of first line,


(y – 2)


y – 2 = √3x


y – √3x – 2 = 0


The equation of line parallel to this line and passing through (0, –2),


(y + 2) = √3x


y – √3x + 2 = 0


Equation of second line,


(y – 2)


y – 2 = –√3x


y + √3x – 2 = 0


The equation of line parallel to this line and passing through (0, –2),


(y + 2) = –√3x


y + √3x + 2 = 0


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