# The equation of t

Given: equation of the base of an equilateral triangle is x + y = 2 and its vertex is (2, -1)

To find: length and equations of its sides

Explanation:

Let A (2, 1) be the vertex of the equilateral triangle ABC and x + y = 2 be the equation of BC.

Diagram: Here, we have to find the equations of the sides AB and AC, each of which makes an angle of 60 with the line x + y = 2

The equations of two lines passing through point x1,y1 and making an angle α with the line whose slope is m is given below: Here,
x1 = 2, y1 = - 1,
α = 60, m = -1

So, the equations of the required sides are and  and   Solving x + y = 2 and , we get:  AB = BC = AC = Hence, equations of its sides are given below: , Rate this question :

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