Q. 6
A line passes through the point (2, 2) and is perpendicular to the line 3x + y = 3. Its y-intercepts is
A. 1/3
B. 2/3
C. 1
D. 4/3
Answer :
The equation of the line perpendicular to 3x + y = 3 is given below:
x – 3y + λ = 0
This line passes through (2, 2).
2 – 6 + λ = 0
⇒ λ = 4
So, the equation of the line will be
x – 3y + 4 = 0
⇒ y = 13x + 43
Hence, the y-intercept is 
.
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