Answer :

Given: (x1,y1) = A(2, 5), tanθ

sin θ and cos θ


To find:


The distance of a point from the line parallel to another line.


Explanation:


So, the equation of the line passing through (2, 5) and having a slope is


Formula Used:



3x – 4y + 14 = 0


Let 3x – 4y + 7 = 0 intersect the line 3x + y + 4 = 0 at point P.


Let AP = r


Then, the coordinate of P are given by



x and y


Thus, the coordinate of P is


Clearly, P lies on the line 3x + y + 4 = 0




3r = – 15


r = – 5


Hence, the distance of the point (2, 5) from the line 3x + y + 4 = 0 is 5


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