Answer :

Given:


Line 3x – 5y + 7 = 0


Concept Used:


Distance of a point from a line.


To find:


The distance of the point (4, 5) from the straight line 3x – 5y + 7 = 0.


Explanation:


Comparing ax + by + c = 0 and 3x 5y + 7 = 0, we get:


a = 3, b = 5 and c = 7


So, the distance of the point (4, 5) from the straight line 3x 5y + 7 = 0 is


d


d


Hence, the required distance is


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