Answer :
Given:
Line 3x – 5y + 7 = 0
Concept Used:
Distance of a point from a line.
To find:
The distance of the point (4, 5) from the straight line 3x – 5y + 7 = 0.
Explanation:
Comparing ax + by + c = 0 and 3x − 5y + 7 = 0, we get:
a = 3, b = − 5 and c = 7
So, the distance of the point (4, 5) from the straight line 3x − 5y + 7 = 0 is
d
⇒ d
Hence, the required distance is 
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