Find the distance of the point (4, 5) from the straight line 3x – 5y + 7 = 0.

Given:

Line 3x – 5y + 7 = 0

Concept Used:

Distance of a point from a line.

To find:

The distance of the point (4, 5) from the straight line 3x – 5y + 7 = 0.

Explanation:

Comparing ax + by + c = 0 and 3x − 5y + 7 = 0, we get:

a = 3, b = − 5 and c = 7

So, the distance of the point (4, 5) from the straight line 3x − 5y + 7 = 0 is

d

⇒ d

Hence, the required distance is