Q. 334.5( 2 Votes )
The ratio in which the line 3x + 4y + 2 = 0 divides the distance between the lines 3x + 4y + 5 = 0 and 3x + 4y – 5 = 0 is
A. 1 : 2
B. 3 : 7
C. 2 : 3
D. 2 : 5
Answer :
The distance between two parallel line 3x + 4y + 5 = 0 and 3x + 4y + 2 = 0 is
The distance between two parallel line 3x + 4y + 2 = 0 and 3x + 4y - 5 = 0 is
Thus required ratio is 
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