Find the equation

A line which is passing through (1,2)

To Find: The equation of a straight line.

Formula used: The equation of line is [y – y₁ = m(x – x₁)]

Explanation: Here,

We know,

According to Pythagoras theorem,

(Hypotenuse)² = (Base)² + (Perpendicular)²

(5)² = (Base)² + (3)²

(Base) =

(Base)² =

Base = 4

Hence,

SO, The slope of the line, m = tan θ

m =

The line passing through (x₁,y₁) = (1,2)

The required equation of line is y – y₁ = m(x – x₁)

y – 2 = (x – 1)

4y – 8 = 3x – 3

3x – 4y + 5 = 0

Hence, The equation of line is 3x – 4y + 5 = 0