Answer :

Given:


Lines y = mx + 1 and 3x + 4y = 9


To find:


The integral values of m


Explanation:


The given lines can be written as


mx – y + 1 = 0 … (1)


3x + 4y – 9 = 0 … (2)


Solving (1) and (2) by cross multiplication, we get:



x


y
For x to be integer we have, 4m + 3 = 1, -1, 5 and -5


m,-1,and -2
Hence, the integral values of m are -1 and -2.


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