Answer :
To find:
The equation of the straight line which cuts off intercepts on x-axis twice that on y-axis and is at a unit distance from the origin.
Assuming:
Intercepts on x-axis and y-axis be 2a and a, respectively.
Explanation:
So, the equation of the line with intercepts 2a on x-axis and a on y-axis be
⇒ x + 2y = 2a … (1)
Let us change equation (1) into normal form.
Thus, the length of the perpendicular from the origin to the line (1) is
Given:
P = 1
Required equation of the line:
x + 2y
⇒ x + 2y + = 0
Hence, equation of required line is x + 2y + = 0.
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