Given: the vertices of triangle ABC are A (4, 3), B (0, 0) and C (2, 3).
The equation of bisector of angle A.
Let us find the lengths of sides AB and AC.
AB = 5
AC = = 2
We know that the internal bisector AD of angle BAC divides BC in the ratio AB: AC, i.e. 5: 2
Thus, the equation of AD is
⇒ x – 3y +5 = 0
Hence, the equation of line is x – 3y +5 = 0
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