Find the equation

Given:

Points A (0, 1), B(2, 0) and C(-1, -2).

Assuming:

m_1, m₂ and m₃ be the slope of the sides AB, BC and CA, respectively.

Concept Used:

The slope of the line passing through the two points ( x₁, y₁) and ( x₂, y₂).

The equation of the line passing through the two points ( x₁, y₁) and ( x₂, y₂).

To find:

The equation of sides of the triangle.

Explanation:

m₁m₂, m₃

m₁, m₂ and m₃= 3

So, the equation of the sides AB, BC and CA are

Formula used: y – y₁= m (x – x₁)

, and y + 2 = 3(x+1)

⇒ x + 2y = 2, 2x – 3y =4 and 3x – y +1 = 0

Hence, equation of sides are x + 2y = 2, 2x – 3y =4 and 3x – y +1 = 0