Find the equation

Given, A straight line passing through the point (6,2) and the slope is – 3

To Find: The equation of the straight line.

Formula used: The equation of line is [y – y₁ = m(x – x₁)]

Explanation: Here, The line is passing through (6,2)

The slope of line, m = – 3 (Given)

Coordinates of line are (x₁,y₁) = (6,2)

The equation of line = y – y₁ = m(x – x₁)

By putting the values, we get

y – 2 = – 3(x – 6)

y – 2 = – 3x + 18

y + 3x – 20 = 0

Hence, The equation of line is y + 3x – 20 = 0