Answer :
Given, A straight line passing through the point (6,2) and the slope is – 3
To Find: The equation of the straight line.
Formula used: The equation of line is [y – y1 = m(x – x1)]
Explanation: Here, The line is passing through (6,2)
The slope of line, m = – 3 (Given)
Coordinates of line are (x1,y1) = (6,2)
The equation of line = y – y1 = m(x – x1)
By putting the values, we get
y – 2 = – 3(x – 6)
y – 2 = – 3x + 18
y + 3x – 20 = 0
Hence, The equation of line is y + 3x – 20 = 0
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