Q. 34

# The coordinates of the foot of the perpendicular from the point (2, 3) on the line x + y – 11 = 0 areA. (-6, 5)B. (3, 4)C. (0, 0)D. (6, 5)

Let the coordinate of the foot of perpendicular from the point (2, 3) on the line x + y – 11 = 0 be (x, y)

Now, the slope of the perpendicular = -1

The equation of perpendicular is given by

y – 3 = 1(x – 2)

= > x – y + 1 = 0

Solving x + y – 11 = 0 and x – y + 1 = 0, we get

ð x = 5 and y = 6

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