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# Find the equation of a line for which

p = 8, α = 300°

Answer :

**Given:** p = 8, α = 300°

**Concept Used:**

Equation of line in normal form.

**Explanation:**

So, the equation of the line in normal form is

**Formula Used:** x cos α + y sin α = p

x cos 300° + y sin 300° = 8

⇒ x cos (360° – 60°) + y sin (360° – 60°) = 8

We know, cos (360° – θ) = cos θ, sin (360° – θ) = – sin θ

⇒ x cos60° – y sin60° = 8

⇒

⇒ x – √3y = 16

**Hence,** the equation of line in normal form is x – √3y = 16

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