# Find the equation of the line, which passes through P(1, -7) and meets the axes at A and B respectively so that 4AP – 3BP = 0.

Concept Used:

The equation of the line with intercepts a and b is

Assuming:

The line meets the coordinate axes at A and B, So the coordinates A (a, 0) and B (0, b )

Given:

4AP – 3BP = 0

Explanation:

AP : BP =3 : 4

Here p= (1, -7)

4a = 7,3b = - 49

a = , b =

Thus the equation of the line is

28x – 3y = 49

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