Q. 135.0( 4 Votes )
Find the equation of the line, which passes through P(1, -7) and meets the axes at A and B respectively so that 4AP – 3BP = 0.
Answer :
Concept Used:
The equation of the line with intercepts a and b is 
Assuming:
The line meets the coordinate axes at A and B, So the coordinates A (a, 0) and B (0, b )
Given:
4AP – 3BP = 0
Explanation:
⇒ AP : BP =3 : 4
Here p= (1, -7)
⇒4a = 7,3b = - 49
⇒a = 
, b = 
Thus the equation of the line is
⇒
⇒ 28x – 3y = 49
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