Answer :
Given:
Lines 4x + 3y – 11 = 0 and 8x + 6y – 15 = 0
To find:
Distance between lines.
Explanation:
The distance between the two parallel lines ax + by + c1 = 0 and ax + by + c2 = 0 is
the given lines can be written as
4x + 3y − 11 = 0 … (1)
8x + 6y – 15 = 0
⇒ … (2)
Let d be the distance between the lines (1) and (2).
Hence,
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