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# Find the equation of the straight line perpendicular to 2x – 3y = 5 and cutting off an intercept 1 on the positive direction of the x-axis.

Given: equation is perpendicular to 2x 3y = 5 and cutting off an intercept 1 on the positive direction of the x-axis.

Explanation:

The line perpendicular to 2x 3y = 5 is

3x + 2y + λ = 0

It is given that the line 3x + 2y + λ = 0 cuts off an intercept of 1 on the positive direction of the x axis.

This means that the line 3x + 2y + λ = 0 passes through the point (1, 0).

3 + 0 + λ = 0

λ = -3

Substituting the value of λ, we get 3x + 2y – 3 = 0,

Hence, equation of the required line.

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