Find the equation of the side BC of the triangle ABC whose vertices are A (-1, -2), B (0, 1) and C (2, 0) respectively. Also, find the equation of the median through A (-1, - 2).

Given: The vertices of triangle ABC are A (-1, -2), B(0, 1) and C(2, 0).

Concept Used:

The equation of the line passing through the two points ( x1, y1) and ( x2, y2)

To find:

Equation of side BC of triangle ABC.

The equation of median through A.

Explanation:

So, the equation of BC is

Formula used:

x + 2y – 2 = 0

Let D be the midpoint of median AD is

So,

So, the equation of the median AD is

Formula used:

4y + 8 = 5x + 5

5x – 4y – 3 = 0

The equation of line BC is x + 2y – 2 = 0

Hence, the equation of median is 5x – 4y – 3 = 0

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