Answer :
Given: equation is perpendicular to and it meets the y-axis.
To find:
The equation of a line drawn perpendicular to the line through the point where it meets the y-axis.
Explanation:
Let us find the intersection of the line with y-axis.
At x = 0,
⇒ y = 6
Thus, the given line intersects y-axis at (0, 6).
The line perpendicular to the line is
This line passes through (0, 6).
⇒ λ
Now, substituting the value of λ, we get:
⇒ 2x -3y + 18 = 0
Hence, the equation of the required line is 2x -3y + 18 = 0
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