Q. 134.0( 4 Votes )
Find the equation of the right bisector of the line segment joining the points (3, 4) and ( – 1, 2).
Answer :
Given, The line segment joining the points (3,4) and ( – 1,2)
To Find: Find the equation of the line
Formula used: The equation of line is (y – y1) = m(x – x1)
Explanation: Here, The right bisector PQ of AB at C and is perpendicular to AB
Now, The coordinate of the mid – points = 
The coordinates of point C are = 
= (1,3)
And, The slope of PQ = 
The slope of PQ, m = 
SO, The slope of PQ, m = – 2
The required equation of PQ is (y – y1) = m(x – x1)
y – 3 = – 2(x – 1)
y – 3 = – 2x + 2
y + 2x = 5
Hence, The equation of line is y + 2x = 5
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The equation of the straight line which passes through the point (-4, 3) such that the portion of the line between the axes is divided internally by the point in the ratio 5 : 3 is
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