# Find the distance

Given: (x1,y1) = A(3, 5), tanθ sin θ and cos θ To find:

The distance of a point from the line parallel to another line.

Explanation:

Formula Used:  x – 2y + 7 = 0

Let x – 2y + 7 = 0 intersect the line 2x + 3y = 14 at point P.

Let AP = r

Then, the coordinate of P is given by x and y Thus, the coordinate of P is Clearly, P lies on the line 2x + 3y = 14   r Hence, the distance of the point (3, 5) from the line 2x + 3y = 14 is Rate this question :

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