Q. 74.3( 6 Votes )
Find the distance of the point (3, 5) from the line 2x + 3y = 14 measured parallel to a line having slope 1/2.
Answer :
Given: (x1,y1) = A(3, 5), tanθ 
⇒ sin θ
and cos θ
To find:
The distance of a point from the line parallel to another line.
Explanation:
Formula Used: 
⇒ 
⇒ x – 2y + 7 = 0
Let x – 2y + 7 = 0 intersect the line 2x + 3y = 14 at point P.
Let AP = r
Then, the coordinate of P is given by
⇒ x 
and y
Thus, the coordinate of P is 
Clearly, P lies on the line 2x + 3y = 14
⇒ 
⇒ 
⇒ r
Hence, the distance of the point (3, 5) from the line 2x + 3y = 14 is 
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