Answer :
The area of a triangle with vertices D (x, 3x), B (− 3, 5) and C (4, − 2) is given below:
Area of ∆DBC 
⇒ Area of ∆DBC = 14x – 7 sq units
Similarly, the area of a triangle with vertices A (6, 3), B (− 3, 5) and C (4, − 2) is given below:
Given:
∆DBC: ∆ABC = 1: 2
⇒ 8x – 4 = 7
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