Answer :

Given: the normal form of a line is x cos θ + y sin θ = p …..… (1)

To find:


P and θ.


Explanation:


Let us try to write down the equation √3 + y + 2 = 0 in its normal form.


Now √3 + y + 2 = 0


√3 + y = – 2


Dividing both sides by 2,


– √3/2 – y/2 = 1


…… (2)


Comparing equations (1) and (2) we get,


and p = 1


θ = 210° = 7π/6 and p = 1


Hence, θ = 210° = 7π/6 and p = 1


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