Answer :

Given: equation is perpendicular to 5x -2y = 8 and pass through mid-point of the line segment joining (2, 3) and (4, 5).


To find:


The equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5).


Explanation:


The line perpendicular to 5x 2y = 8 is 2x + 5y + λ = 0


Coordinates of the mid points of (2,3) and (4,5)


6 + 20 + λ = 0


λ = -26


Substituting the value of λ,


We get 2x + 5y-26 = 0,


Hence, the required equation of line is 2x + 5y-26 = 0.


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