Q. 95.0( 1 Vote )

# Find the equation

Given: equation is perpendicular to 5x -2y = 8 and pass through mid-point of the line segment joining (2, 3) and (4, 5).

To find:

The equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5).

Explanation:

The line perpendicular to 5x 2y = 8 is 2x + 5y + λ = 0

Coordinates of the mid points of (2,3) and (4,5)

6 + 20 + λ = 0

λ = -26

Substituting the value of λ,

We get 2x + 5y-26 = 0,

Hence, the required equation of line is 2x + 5y-26 = 0.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Find the equationRS Aggarwal - Mathematics

Find the equationRS Aggarwal - Mathematics

Find the equationRS Aggarwal - Mathematics

Find the equationRD Sharma - Mathematics

Find the equationRD Sharma - Mathematics

If equation of thRD Sharma - Mathematics

Find the equationRS Aggarwal - Mathematics

Find the image ofRS Aggarwal - Mathematics

A line passes thrRD Sharma - Mathematics

<span lang="EN-USRS Aggarwal - Mathematics