Q. 95.0( 1 Vote )

Find the equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5).

Answer :

Given: equation is perpendicular to 5x -2y = 8 and pass through mid-point of the line segment joining (2, 3) and (4, 5).


To find:


The equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5).


Explanation:


The line perpendicular to 5x 2y = 8 is 2x + 5y + λ = 0


Coordinates of the mid points of (2,3) and (4,5)


6 + 20 + λ = 0


λ = -26


Substituting the value of λ,


We get 2x + 5y-26 = 0,


Hence, the required equation of line is 2x + 5y-26 = 0.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Various Forms of Equations of line45 mins
Parametric Equations of Straight line48 mins
Straight line | Analyse your learning through quiz56 mins
Slope, inclination and angle between two lines48 mins
Interactive Quiz on Equations of line23 mins
General Equation of a line43 mins
Motion in a Straight Line - 0665 mins
Motion in a Straight Line - 0556 mins
Motion in a Straight Line - 0372 mins
Motion in a Straight Line - 1169 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses