# Prove that the area of the parallelogram formed by the lines 3x – 4y + a = 0, 3x – 4y + 3a = 0, 4x – 3y – a = 0 and 4x – 3y – 2a = 0 is sq. units.

Given:

The given lines are

3x 4y + a = 0 … (1)

3x 4y + 3a = 0 … (2)

4x 3y a = 0 … (3)

4x 3y 2a = 0 … (4)

To prove:

The area of the parallelogram formed by the lines 3x – 4y + a = 0, 3x – 4y + 3a = 0, 4x – 3y – a = 0 and 4x – 3y – 2a = 0 is sq. units.

Explanation:

From Above solution, We know that

Area of the parallelogram

Area of the parallelogramsquare units

Hence proved.

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