Answer :
Given: p = 4, α = 150°
Concept Used:
Equation of line in normal form.
Explanation:
So, the equation of the line in normal form is
Formula Used: x cos α + y sin α = p
x cos 150° + y sin 150° = 4
cos (180° – θ) = – cos θ , sin (180° – θ) = sin θ
⇒ x cos(180° – 30°) + y sin(180° – 30°) = 4
⇒ – x cos 30° + y sin 30° = 4
⇒
⇒ √3x – y + 8 = 0
Hence, the equation of line in normal form is √3 x – y + 8 = 0
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
<span lang="EN-US
RS Aggarwal - MathematicsThe distance betw
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal - MathematicsFind the equation
RD Sharma - MathematicsFind the equation
RD Sharma - MathematicsArea of the trian
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - Mathematics<span lang="EN-US
RD Sharma - MathematicsA point equidista
RD Sharma - Mathematics