Q. 3 B4.6( 5 Votes )
Find the area of the triangle formed by the lines
y = 0, x = 2 and x + 2y = 3
Answer :
Given:
y = 0 … (1)
x = 2 … (2)
x + 2y = 3 … (3)
Assuming:
In triangle ABC, let equations (1), (2) and (3) represent the sides AB, BC and CA, respectively.
Concept Used:
Point of intersection of two lines.
Explanation:
Solving (1) and (2):
x = 2, y = 0
Thus, AB and BC intersect at B (2, 0).
Solving (1) and (3):
x = 3, y = 0
Thus, AB and CA intersect at A (3, 0).
Similarly, solving (2) and (3):
x = 2, y = 12
Thus, BC and CA intersect at C(2, 12).
∴ Area of triangle ABC = 
Hence, area of triangle ABC is 
.
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