Answer :

Given: The vertices of ABC are A (1, 4), B ( 3, 2) and C ( 5, 3).


To find:


The equations of the altitudes of a ΔABC whose vertices are A (1, 4), B (-3, 2) and C (-5, -3).


Explanation:


Diagram:



Slope of AB


Slope of BC


Slope of CA


Thus, we have:


Slope of CF = -2


Slope of AD


Slope of BE


Hence,


Equation of CF is: y + 3 = -2(x + 5)


2x + y + 13 = 0


Equation of AD is: y – 4(x – 1)


2x + 5y – 22 = 0


Equation of BE is: y – 2(x + 3)


6x + 7y + 4 = 0


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