Q. 44.3( 3 Votes )

# Find the equation

Given: The vertices of ABC are A (1, 4), B ( 3, 2) and C ( 5, 3).

To find:

The equations of the altitudes of a ΔABC whose vertices are A (1, 4), B (-3, 2) and C (-5, -3).

Explanation:

Diagram: Slope of AB Slope of BC Slope of CA Thus, we have:

Slope of CF = -2

Slope of AD Slope of BE Hence,

Equation of CF is: y + 3 = -2(x + 5)

2x + y + 13 = 0

Equation of AD is: y – 4 (x – 1)

2x + 5y – 22 = 0

Equation of BE is: y – 2 (x + 3)

6x + 7y + 4 = 0

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