Q. 14.4( 7 Votes )

Find the equation of the parallel to x–axis and passing through (3, – 5).

Answer :

Given, A line which is parallel to x–axis and passing through (3, – 5)

To Find: The equation of the line.


Formula used: The equation of line is [y – y1 = m(x – x1)]


Explanation: Here, The line is parallel to the x–axis,


So, The parallel lines have equal slopes,


And, the slope of x–axis is always 0, then


The slope of line, m = 0


Coordinates of line are (x1, y1) = (3, – 5)


The equation of line = y – y1 = m(x – x1)


By putting the values, we get


y – (– 5) = 0(x – 3)


y + 5 = 0


Hence, The equation of line is y + 5 = 0


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