Answer :
A line perpendicular to 3x − 5y + 7 = 0 is given by
5x + 3y + λ = 0
This line passes through (1, 5).
5 + 15 + λ = 0
⇒ λ = – 20
Therefore, the equation of the required line is 5x + 3y – 20 = 0
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