Q. 195.0( 2 Votes )

If equation of the line passing through (1, 5) and perpendicular to the line 3x – 5y + 7 = 0 is
A. 5x + 3y – 20 = 0

B. 3x – 5y + 7 = 0

C. 3x – 5y + 6 = 0

D. none of these

Answer :

A line perpendicular to 3x 5y + 7 = 0 is given by


5x + 3y + λ = 0


This line passes through (1, 5).


5 + 15 + λ = 0


λ = – 20


Therefore, the equation of the required line is 5x + 3y – 20 = 0

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