# If equation of the line passing through (1, 5) and perpendicular to the line 3x – 5y + 7 = 0 isA. 5x + 3y – 20 = 0B. 3x – 5y + 7 = 0C. 3x – 5y + 6 = 0D. none of these

A line perpendicular to 3x 5y + 7 = 0 is given by

5x + 3y + λ = 0

This line passes through (1, 5).

5 + 15 + λ = 0

λ = – 20

Therefore, the equation of the required line is 5x + 3y – 20 = 0

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