# <span lang="EN-US

Given: (x1,y1) = A(2,5)

To find:

The distance of a point from the line parallel to another line.

Explanation:

It is given that the required line is parallel to 3x −4y + 8 = 0

4y = 3x + 8

y tanθ sinθ , cosθ So, the equation of the line is  3x – 6 = 4y – 20

3x – 4y + 14 = 0

Let the line 3x – 4y + 14 = 0 cut the line 3x + y + 4 = 0 at P.

Let AP = r Then, the coordinates of P are given by x , y Thus, the coordinates of P are Clearly, P lies on the line 3x + y + 4 = 0.   r = – 5

AP = |r| = 5

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

<span lang="EN-USRS Aggarwal - Mathematics

The distance betwRD Sharma - Mathematics

<span lang="EN-USRS Aggarwal - Mathematics

Find the equationRD Sharma - Mathematics

Find the equationRD Sharma - Mathematics

Area of the trianRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

A point equidistaRD Sharma - Mathematics