Q. 105.0( 4 Votes )

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Answer :

Given: (x1,y1) = A(2,5)

To find:


The distance of a point from the line parallel to another line.


Explanation:


It is given that the required line is parallel to 3x −4y + 8 = 0


4y = 3x + 8


y


tanθ


sinθ, cosθ


So, the equation of the line is




3x – 6 = 4y – 20


3x – 4y + 14 = 0


Let the line 3x – 4y + 14 = 0 cut the line 3x + y + 4 = 0 at P.


Let AP = r Then, the coordinates of P are given by



x, y


Thus, the coordinates of P are


Clearly, P lies on the line 3x + y + 4 = 0.





r = – 5


AP = |r| = 5


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