Answer :

The equation of the sides AB, BC and CA of ABC are y x = 2, x + 2y = 1 and 3x + y + 5 = 0, respectively.


Solving the equations of AB and BC, i.e. y x = 2 and x + 2y = 1, we get:


x = 1, y = 1


So, the coordinates of B are ( 1, 1).


The altitude through B is perpendicular to AC.


Slope of AC = -3


Thus, slope of the altitude through B is 13.


Equation of the required altitude is given below:


y – 1 = 13x + 1


x – 3y + 4 = 0

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