# <span lang="EN-US

Given:

lines x + y = 4 and 2x – 3y = 1

To find:

The equation of the straight line drawn through the point of intersection of the lines x + y = 4 and 2x – 3y = 1 and perpendicular to the line cutting off intercepts 5, 6 on the axes.

Explanation:

The equation of the straight line passing through the point of intersection of x + y = 4 and 2x 3y = 1 is

x + y 4 + λ(2x 3y 1) = 0

(1 + 2λ)x + (1 3λ)y 4 λ = 0 … (1)

y The equation of the line with intercepts 5 and 6 on the axis is … (2)

The slope of this line is The lines (1) and (2) are perpendicular. λ Substituting the values of λ in (1), we get the equation of the required line. 25x – 30y – 23 = 0

Hence, required equation is 25x – 30y – 23 = 0

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

If a + b + c = 0,RD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

Find the equationRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics

<span lang="EN-USRD Sharma - Mathematics