Q. 26
Three vertices of a parallelogram taken in order are (-1, -6), (2, -5) and (7, 2). The fourth vertex is
A. (1, 4)
B. (4, 1)
C. (1, 1)
D. (4, 4)
Answer :
Let A (− 1, − 6), B(2, − 5) and C(7, 2) be the given vertex.
Let D(h, k) be the fourth vertex.
The midpoints of AC and BD are 
and 
respectively.
We know that the diagonals of a parallelogram bisect each other .
⇒ h = 4 and k = 1
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